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a^2=120^2=250^2
We move all terms to the left:
a^2-(120^2)=0
We add all the numbers together, and all the variables
a^2-14400=0
a = 1; b = 0; c = -14400;
Δ = b2-4ac
Δ = 02-4·1·(-14400)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*1}=\frac{-240}{2} =-120 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*1}=\frac{240}{2} =120 $
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